4x^2+124x+9=0

Solution for 4x^2+124x+9=0 equation:

4x^2+124x+9=0

a = 4; b = 124; c = +9;
Δ = b2-4ac
Δ = 1242-4·4·9
Δ = 15232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15232}=\sqrt{64*238}=\sqrt{64}*\sqrt{238}=8\sqrt{238}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(124)-8\sqrt{238}}{2*4}=\frac{-124-8\sqrt{238}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(124)+8\sqrt{238}}{2*4}=\frac{-124+8\sqrt{238}}{8}
$